Transfer Function From Bode Plot

Quick Answer

A Bode plot displays a transfer function's frequency response as two graphs: magnitude |H(jω)| in dB and phase ∠H(jω) in degrees versus log frequency. To plot from a transfer function: factor H(s) into standard forms (gains, poles, zeros), draw asymptotic approximations, then refine at corner frequencies. To extract a transfer function from a Bode plot: identify the DC gain, locate corner frequencies (slope changes), determine the order from asymptotic slopes (−20 dB/dec per pole, +20 dB/dec per zero), and reconstruct H(s). Compute Bode plots at www.lapcalc.com.

Transfer Function from Bode Plot

Extracting a transfer function from a measured or given Bode plot is a key engineering skill. Step 1: identify the low-frequency (DC) gain — the magnitude value as ω → 0 gives 20log|H(0)| dB. Step 2: locate corner frequencies (break frequencies) where the magnitude slope changes — each slope change of −20 dB/dec indicates a pole, each +20 dB/dec indicates a zero. Step 3: determine the system order from the high-frequency slope (−20n dB/dec for n excess poles). Step 4: check for complex poles by looking for resonance peaks (magnitude > asymptotic value near the corner frequency, indicating ζ < 0.707). Step 5: reconstruct: H(s) = K·∏(s/ω_zi + 1)/∏(s/ω_pi + 1) using the identified DC gain K, zero frequencies ω_zi, and pole frequencies ω_pi. Verify against the phase plot for consistency.

Key Formulas

How to Draw a Bode Plot from a Transfer Function

Given H(s), plotting the Bode diagram follows a systematic procedure. Step 1: rewrite H(s) in standard (time-constant) form with all factors as (1 + s/ω_c): H(s) = K·∏(1+s/ω_zi)/∏(1+s/ω_pi). Step 2: identify the DC gain K₀ = |H(0)| and plot 20log(K₀) dB as the starting magnitude. Step 3: for each pole at ω_pi, the magnitude drops −20 dB/dec starting at ω = ω_pi, and the phase decreases by −90° centered at ω_pi. Step 4: for each zero at ω_zi, the magnitude rises +20 dB/dec starting at ω = ω_zi, and the phase increases by +90°. Step 5: for integrators (1/s), the magnitude is a −20 dB/dec line through 0 dB at ω = 1, and the phase is constant −90°. Step 6: sum all individual contributions (Bode plots are additive in dB and degrees). Step 7: refine near corner frequencies where the actual curve deviates from asymptotes by ±3 dB.

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Bode Diagram Transfer Function: Standard Forms

Common transfer function factors and their Bode contributions. Constant gain K: flat magnitude at 20log|K| dB, phase 0° (K > 0) or −180° (K < 0). Integrator 1/s: −20 dB/dec magnitude through 0 dB at ω = 1, constant −90° phase. Differentiator s: +20 dB/dec, constant +90° phase. First-order pole 1/(1+s/ωp): 0 dB below ωp, −20 dB/dec above ωp, phase from 0° to −90° (−45° at ωp). First-order zero (1+s/ωz): 0 dB below ωz, +20 dB/dec above ωz, phase from 0° to +90°. Second-order poles 1/(1+2ζs/ωn+s²/ωn²): 0 dB below ωn, −40 dB/dec above ωn, with resonance peak of 1/(2ζ) at ω ≈ ωn for ζ < 0.707, phase from 0° to −180°. Time delay e^(−sθ): 0 dB magnitude (flat), phase decreasing linearly: −ωθ radians.

Plotting Bode Plots from Transfer Functions: Example

Example: H(s) = 100(s+10)/[s(s+1)(s+100)]. Rewrite in standard form: H(s) = [100·10/(1·100)] · (1+s/10)/[s·(1+s/1)·(1+s/100)] = 10·(1+s/10)/[s·(1+s)·(1+s/100)]. DC gain (excluding integrator): K₀ = 10 → 20 dB. Start with integrator: −20 dB/dec line through 20 dB at ω = 1. At ω = 1: pole adds −20 dB/dec → slope becomes −40 dB/dec. At ω = 10: zero adds +20 dB/dec → slope becomes −20 dB/dec. At ω = 100: pole adds −20 dB/dec → slope becomes −40 dB/dec. Phase: starts at −90° (integrator), decreases further past ω = 1 pole, recovers at ω = 10 zero, decreases again past ω = 100 pole. MATLAB: bode(tf([100 1000],[1 101 100 0])) confirms this analysis.

Bode Plot Applications in Control Design

Bode plots are the primary frequency-domain design tool for feedback controllers. Stability margins: gain margin GM = −|H(jω₁₈₀)| dB (at phase = −180°) and phase margin PM = 180° + ∠H(jωc) (at |H| = 0 dB) are read directly from the Bode plot. Controller design: lead compensation adds phase near the crossover frequency (increasing PM), lag compensation adds low-frequency gain (reducing steady-state error). PID tuning: the PID Bode plot shows the integral's +20 dB/dec at low frequencies (for accuracy) and the derivative's +20 dB/dec at mid frequencies (for phase lead). System identification: measured frequency response data (from swept-sine tests or FFT analysis) is plotted as a Bode diagram, then a transfer function model is fit to the data. The transfer functions are computed in the Laplace domain at www.lapcalc.com.

Related Topics in transfer function concepts

Understanding transfer function from bode plot connects to several related concepts: bode diagram transfer function, plotting bode plots from transfer functions, how to draw a bode plot from a transfer function, and how to make bode plot from transfer function. Each builds on the mathematical foundations covered in this guide.

Frequently Asked Questions

Identify DC gain from low-frequency magnitude. Locate corner frequencies where slopes change: −20 dB/dec per pole, +20 dB/dec per zero. Check for resonance peaks (complex poles). Reconstruct H(s) = K·∏(1+s/ωz)/∏(1+s/ωp). Verify against the phase plot for consistency.

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